Toshiba 2000 V Series Manual

Also see for 2000 V Series: User manual

6F8C0845 413.5 Network Power/Grounding3Figure 3-14 Example of Solution to an Overload(a) Total current consumption of section 1 =1.1A+1.25A=2.35A(a’) Total current consumption of section 2 =0.5A+0.25A+0.25A+0.85A=1.85(b) Overall power cable length of section 1 = 100m(b’) Overall power cable length of section 2 = 140m(c) Maximum current that can be supplied to the cables in section 1 based on Figure3-10 = 2.93 A(c’) Maximum current that can be supplied to the cables in section 2 based on Figure3-10 = About 2.19 A (Obtained by linear approximation of 100 to 150 m)(d) Since the total current consumption of both sections 1 and 2 is smaller than themaximum current, power can be supplied to all the nodes by single power unitcentral connection.(e) Install a network power unit with a rated current capacity of 4.2 A or more.(Select one with an adequate capacity, considering the conditions of use.)Node 6Node 5Node 4Node 1Node 2Node 3ネットワーク電源供給装置電源タップセクション 1100 mV +−1.1A 1.25A V − 0.5A 0.25A 0.25A 0.85Aセクション 2140 mSection 1 Section 2PowertapNetwork powerunit