Application ExamplesIP 267Figure 6-6. Example of Moment of Inertia as a Function of f SS500600 2500 Hz300 Revs/min20002407.56.255.03.752.51.2510001201500180Moment of inertiaJ[kg cm2]A start/stop rate of f ss = 320 Hz was selected for this example. The followingtherefore applies:f ss = BV * SS * R320 Hz = 40 * SS * 1SS = 8The value calculated for SS is coded with bits 0 to 7 of byte 0 of the configurationmessage frame and written into QB 88 of the PIQ ( Table 6-2.).The following applies for this example: QB 88 = 00001000 = 08 H6-28EWA 4NEB 812 6061-02a