hp calculatorsHP 10BII Statistics – Rearranging Itemshp calculators - 2 - HP 10BII Statistics – Rearranging Items - Version 1.0Statistics on the HP 10BIIThe HP 10BII has many built-in statistics functions that apply to finding averages and standard deviations as well aslinear regression, correlation and rearranging items.Rearranging itemsThere are a great number of applications that involve determining the number of ways a group of items can berearranged. The factorial function, accessed by pressing yellow shift U…on the HP 10BII, will determine the numberof ways you can rearrange the total number of items in a group.To determine the number of ways you can select a subgroup of a specified number of items from a larger group, wherethe order of each of the items in the subgroup is important, the permutation formula is used, as shown in figure 1 below.The formula indicates the permutations of n items taken r at a time.)!(!rnnnPermutatio −= Figure 1To determine the number of ways you can select a subgroup of a specified number of items from a larger group, wherethe order of each of the items in the subgroup is not important, the combination formula is used, as shown in figure 2below. The formula indicates the combinations of n items taken r at a time.)!(!!rnrnnCombinatio −= Figure 2To see the difference between permutations and combinations, consider the set of three items A, B, and C. If we select asubgroup of 2 items, we could select AC and CA as two possible subgroups. These would be counted as differentsubgroups if computing the number of permutations, but only as one subgroup if computing the number of combinations.Factorials show up throughout mathematics and statistics. Permutations and combinations show up in many discreteprobability distribution calculations, such as the binomial and hypergeometric distributions.Practice solving problems involving rearranging itemsExample 1: How many different ways could 4 people be seated at a table?Solution: 4U…Answer: 24.Example 2: How many different hands of 5 cards could be dealt from a standard deck of 52 cards? Assume the orderof the cards in the hand does not matter.Solution: Since the order of the cards in the hand does not matter, the problem is solved as a combination.52U…/Us5U…*Us52-5UtU…Ut=